ka板VFD安装

chenghj

记号一下

iamusb

支持，越看越对VFD兴趣越大了
我手上的也想点亮试一下

naoki

记号再顶

zhengdahe

请问楼主数据转换部分的程序怎么理解啊，看不懂，也没有详细注释，请帮忙解释下吧
void VFD_Disp(void)
{
unsigned char base_a, temp=0, g_temp,i;
g_temp = 42 - (g >> 3);
i = (g & 7);
if (i == 0)
{
//*******************************TBlank start*******************************//
  G_BK_SET;
  _delay_us(3);
  G_LAT_SET;
  _delay_us(1);
  G_LAT_CLR;
  _delay_us(1);
  G_BK_CLR;
//*******************************TBlank stot********************************//
//   if (g >= 43)
  if (g >= 344)
  {
   g=0;
   G_CLK_CLR;
   G_SI_SET;
   G_CLK_SET;
   G_CLK_CLR;
   G_CLK_SET;
   G_SI_CLR;
   G_CLK_CLR;
   G_CLK_SET;
   G_CLK_CLR;
   G_CLK_SET;
   G_CLK_CLR;
   G_CLK_SET;
  }
  G_CLK_CLR;
  G_CLK_SET;
}
// base_a = (g_temp>>1) * 6;
base_a = g_temp * 3;
if (g_temp & 0x1)
{
  //双数列
//第一行
  /*     temp = ((buff[i][base_a+5] & 1)) << 1;
     temp |= ((buff[i][base_a+4] & 1)) << 3;
     temp |= ((buff[i][base_a+3] & 1)) << 5;
     temp |= ((buff[i][base_a+5] & 2)) << 6;
  */   temp = 0;
  if (buff[i][base_a+2] & 1) temp = 2;
  if (buff[i][base_a+1] & 1) temp |= 8;
  if (buff[i][base_a] & 1) temp |= 0x20;
//第一行
//第二行
  if (buff[i][base_a+2] & 2) temp |= 0x80;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp  = buff[i][base_a+1] & 2;
  if (buff[i][base_a] & 2) temp |= 8;
//第二行
//第三行
  if (buff[i][base_a+2] & 4) temp |= 0x20;
  if (buff[i][base_a+1] & 4) temp |= 0x80;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
  if (buff[i][base_a] & 4) temp  |= 2;
//第三行
//第四行
  temp |= buff[i][base_a+2] & 8;
  if (buff[i][base_a+1] & 8) temp |= 0x20;
  if (buff[i][base_a] & 8) temp |= 0x80;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
//第四行
//第五行
  if (buff[i][base_a+2] & 0x10) temp = 2;
  if (buff[i][base_a+1] & 0x10) temp |= 8;
  if (buff[i][base_a] & 0x10) temp |= 0x20;
//第五行
//第六行
  if (buff[i][base_a+2] & 0x20) temp |= 0x80;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
  if (buff[i][base_a+1] & 0x20) temp = 2;
  if (buff[i][base_a] & 0x20) temp |= 8;
//第六行
//第七行
  if (buff[i][base_a+2] & 0x40) temp |= 0x20;
  if (buff[i][base_a+1] & 0x40) temp |= 0x80;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
  if (buff[i][base_a] & 0x40) temp = 2;
//第七行
//第八行
  if (buff[i][base_a+2] & 0x80) temp |= 8;
  if (buff[i][base_a+1] & 0x80) temp |= 0x20;
  temp |= buff[i][base_a] & 0x80;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
//第八行
//    }
} else {
  //单数列
//    for (i=0; i<8; i++)
//  {
//第一行
  temp  = buff[i][base_a] & 1;
  if (buff[i][base_a+1] & 1) temp |= 4;
  if (buff[i][base_a+2] & 1) temp |= 0x10;
//第一行
//第二行
  if (buff[i][base_a]   & 2) temp |= 0x40;
//     while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
  if (buff[i][base_a+1] & 2) temp  = 1;
  if (buff[i][base_a+2] & 2) temp |= 4;
//第二行
//第三行
  if (buff[i][base_a]   & 4) temp |= 0x10;
  if (buff[i][base_a+1] & 4) temp |= 0x40;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
  if (buff[i][base_a+2] & 4) temp  = 1;
//第三行
//第四行
  if (buff[i][base_a]   & 8) temp |= 4;
  if (buff[i][base_a+1] & 8) temp |= 0x10;
  if (buff[i][base_a+2] & 8) temp |= 0x40;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
//第四行
//第五行
  if (buff[i][base_a]   & 0x10) temp = 1;
  if (buff[i][base_a+1] & 0x10) temp |= 4;
  temp |= buff[i][base_a+2] & 0x10;
//第五行
//第六行
  if (buff[i][base_a]   & 0x20) temp |= 0x40;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
  if (buff[i][base_a+1] & 0x20) temp = 1;
  if (buff[i][base_a+2] & 0x20) temp |= 4;
//第六行
//第七行
  if (buff[i][base_a]   & 0x40) temp |= 0x10;
  temp |= buff[i][base_a+1] & 0x40;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
  temp = 0;
  if (buff[i][base_a+2] & 0x40) temp = 1;
//第七行
//第八行
  if (buff[i][base_a]   & 0x80) temp |= 4;
  if (buff[i][base_a+1] & 0x80) temp |= 0x10;
  if (buff[i][base_a+2] & 0x80) temp |= 0x40;
  while(!(SPSR & BIT(SPIF)));
  SPDR = temp;
//第八行
//    }
}
g++;
}

kazuyuki

请问楼主数据转换部分的程序怎么理解啊，看不懂，也没有详细注释，请帮忙解释下吧
void VFD_Disp(void)
{ ...
zhengdahe 发表于 2012-4-9 21:05 https://www.yleee.com.cn/images/common/back.gif

    这个时序比较复杂，首先是生成G的时钟和数据位，然后根据G的位置，按a1,b1,c1,a2,b2,c2...a64,b64,c65的顺序（G是单数）或f1,e1,d1,f2,e2,d2,...,f64,e64,d64的顺序送出数据。其中abc中间插入0，变成a0b0c0顺序，def也一样，0f0e0d的顺序送出。

zhengdahe

数据取模的时候应该是列行式的吧？

kazuyuki

对，纵向8个点为一字节

dingdao

睡前一顶~~~~~~~~~~~~

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luannan

太复杂了，还是等老大的模拟吧！

key

时钟加上刻度更好